Optimal. Leaf size=143 \[ \frac{a (3 a+4 b) \tanh ^{-1}\left (\frac{\sqrt{a+b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{8 f (a+b)^{3/2}}+\frac{\tan (e+f x) \sec ^3(e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{4 f (a+b)}+\frac{(3 a+4 b) \tan (e+f x) \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{8 f (a+b)} \]
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Rubi [A] time = 0.139333, antiderivative size = 143, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3190, 382, 378, 377, 206} \[ \frac{a (3 a+4 b) \tanh ^{-1}\left (\frac{\sqrt{a+b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{8 f (a+b)^{3/2}}+\frac{\tan (e+f x) \sec ^3(e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2}}{4 f (a+b)}+\frac{(3 a+4 b) \tan (e+f x) \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{8 f (a+b)} \]
Antiderivative was successfully verified.
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Rule 3190
Rule 382
Rule 378
Rule 377
Rule 206
Rubi steps
\begin{align*} \int \sec ^5(e+f x) \sqrt{a+b \sin ^2(e+f x)} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\sqrt{a+b x^2}}{\left (1-x^2\right )^3} \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac{\sec ^3(e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2} \tan (e+f x)}{4 (a+b) f}+\frac{(3 a+4 b) \operatorname{Subst}\left (\int \frac{\sqrt{a+b x^2}}{\left (1-x^2\right )^2} \, dx,x,\sin (e+f x)\right )}{4 (a+b) f}\\ &=\frac{(3 a+4 b) \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)} \tan (e+f x)}{8 (a+b) f}+\frac{\sec ^3(e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2} \tan (e+f x)}{4 (a+b) f}+\frac{(a (3 a+4 b)) \operatorname{Subst}\left (\int \frac{1}{\left (1-x^2\right ) \sqrt{a+b x^2}} \, dx,x,\sin (e+f x)\right )}{8 (a+b) f}\\ &=\frac{(3 a+4 b) \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)} \tan (e+f x)}{8 (a+b) f}+\frac{\sec ^3(e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2} \tan (e+f x)}{4 (a+b) f}+\frac{(a (3 a+4 b)) \operatorname{Subst}\left (\int \frac{1}{1-(a+b) x^2} \, dx,x,\frac{\sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{8 (a+b) f}\\ &=\frac{a (3 a+4 b) \tanh ^{-1}\left (\frac{\sqrt{a+b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{8 (a+b)^{3/2} f}+\frac{(3 a+4 b) \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)} \tan (e+f x)}{8 (a+b) f}+\frac{\sec ^3(e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2} \tan (e+f x)}{4 (a+b) f}\\ \end{align*}
Mathematica [C] time = 14.3778, size = 669, normalized size = 4.68 \[ -\frac{\tan (e+f x) \sec ^3(e+f x) \left (\frac{b \sin ^2(e+f x)}{a}+1\right ) \left (10 b \sin ^2(e+f x) \sqrt{-\frac{(a+b) \tan ^2(e+f x) \sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a^2}}+15 a \sqrt{-\frac{(a+b) \tan ^2(e+f x) \sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a^2}}+32 b \sin ^2(e+f x) \left (-\frac{(a+b) \tan ^2(e+f x)}{a}\right )^{7/2} \, _2F_1\left (2,4;\frac{7}{2};-\frac{(a+b) \tan ^2(e+f x)}{a}\right ) \sqrt{\frac{\sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a}}+32 a \left (-\frac{(a+b) \tan ^2(e+f x)}{a}\right )^{7/2} \, _2F_1\left (2,4;\frac{7}{2};-\frac{(a+b) \tan ^2(e+f x)}{a}\right ) \sqrt{\frac{\sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a}}-32 b \sin ^2(e+f x) \left (-\frac{(a+b) \tan ^2(e+f x)}{a}\right )^{5/2} \, _2F_1\left (2,4;\frac{7}{2};-\frac{(a+b) \tan ^2(e+f x)}{a}\right ) \sqrt{\frac{\sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a}}-32 a \left (-\frac{(a+b) \tan ^2(e+f x)}{a}\right )^{5/2} \, _2F_1\left (2,4;\frac{7}{2};-\frac{(a+b) \tan ^2(e+f x)}{a}\right ) \sqrt{\frac{\sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a}}-10 b \sin ^2(e+f x) \sin ^{-1}\left (\sqrt{-\frac{(a+b) \tan ^2(e+f x)}{a}}\right )-15 a \sin ^{-1}\left (\sqrt{-\frac{(a+b) \tan ^2(e+f x)}{a}}\right )-20 b \sin ^2(e+f x) \left (-\frac{(a+b) \tan ^2(e+f x)}{a}\right )^{3/2} \sqrt{\frac{\sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a}}-30 a \left (-\frac{(a+b) \tan ^2(e+f x)}{a}\right )^{3/2} \sqrt{\frac{\sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a}}\right )}{40 f \sqrt{a+b \sin ^2(e+f x)} \left (-\frac{(a+b) \tan ^2(e+f x)}{a}\right )^{3/2} \sqrt{\frac{\sec ^2(e+f x) \left (a+b \sin ^2(e+f x)\right )}{a}}} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 4.52, size = 570, normalized size = 4. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{b \sin \left (f x + e\right )^{2} + a} \sec \left (f x + e\right )^{5}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 5.38284, size = 1079, normalized size = 7.55 \begin{align*} \left [\frac{{\left (3 \, a^{2} + 4 \, a b\right )} \sqrt{a + b} \cos \left (f x + e\right )^{4} \log \left (\frac{{\left (a^{2} + 8 \, a b + 8 \, b^{2}\right )} \cos \left (f x + e\right )^{4} - 8 \,{\left (a^{2} + 3 \, a b + 2 \, b^{2}\right )} \cos \left (f x + e\right )^{2} - 4 \,{\left ({\left (a + 2 \, b\right )} \cos \left (f x + e\right )^{2} - 2 \, a - 2 \, b\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b} \sqrt{a + b} \sin \left (f x + e\right ) + 8 \, a^{2} + 16 \, a b + 8 \, b^{2}}{\cos \left (f x + e\right )^{4}}\right ) + 4 \,{\left ({\left (3 \, a^{2} + 5 \, a b + 2 \, b^{2}\right )} \cos \left (f x + e\right )^{2} + 2 \, a^{2} + 4 \, a b + 2 \, b^{2}\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b} \sin \left (f x + e\right )}{32 \,{\left (a^{2} + 2 \, a b + b^{2}\right )} f \cos \left (f x + e\right )^{4}}, -\frac{{\left (3 \, a^{2} + 4 \, a b\right )} \sqrt{-a - b} \arctan \left (\frac{{\left ({\left (a + 2 \, b\right )} \cos \left (f x + e\right )^{2} - 2 \, a - 2 \, b\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b} \sqrt{-a - b}}{2 \,{\left ({\left (a b + b^{2}\right )} \cos \left (f x + e\right )^{2} - a^{2} - 2 \, a b - b^{2}\right )} \sin \left (f x + e\right )}\right ) \cos \left (f x + e\right )^{4} - 2 \,{\left ({\left (3 \, a^{2} + 5 \, a b + 2 \, b^{2}\right )} \cos \left (f x + e\right )^{2} + 2 \, a^{2} + 4 \, a b + 2 \, b^{2}\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b} \sin \left (f x + e\right )}{16 \,{\left (a^{2} + 2 \, a b + b^{2}\right )} f \cos \left (f x + e\right )^{4}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{b \sin \left (f x + e\right )^{2} + a} \sec \left (f x + e\right )^{5}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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